MOON LANDING HOAX A Moon Landing (After Space Travel) is physically not possible. I have 2 methods on proving my case: 1ST PROOF: LAW OF ARCHIMIDES IN DENSITY: DENSITY EQUALS WEIGHT DEVIDED BY VOLUME ( d= W/V) Whereas WEIGHT EQUALS MASS BY ACCELERATION OF GRAVITY (W= mg) ...Therefore, density = (mg)/V The liquid and gas volumes have to have the same density values here on Earth and on the Moon, otherwise spacemen (astronauts) cannot breathe the air and their blood cannot have the same density. If d1 is the density on Earth, and d2 is the density on the Moon Therefore, d1 has to be equal to d2 d1=d2 (m1g1)/V1 has to be equal to (m2g2)/V2 (m1g1)/V1 = (m2g2)/V2 Since m and V are the same on both sides of the equation, therefore, the g1 and g2 has to be equal as well. We all know that the gravity on the Moon is 1/6 of Earth. This means, if spacemen would ever go to moon one day, they have to have devices so (could be) called “gravity adjusters”, whereas the missing gravital forces has to be maintained otherwise the spacemen would die due to the fact that the air that they breath and the blood that they have in their blood vessels would take up more volume than they do on Earth. Therefore, the astronauts would die instantly. 2ND PROOF: THE ATMOSPHERICAL PRESSURE CRITERIA air density = 1.225 kg/m³ (0.0765 lb/cu ft) If we take a glass filled up with water completely, and place a piece of paper on top of it, and when we turn the glass upside down, the water (inside of the glass) does not fall on to the ground since there is atmospheric pressure under the paper. Therefore, P(atm) = W(water) = mg(water) P(atm) = P(water) = hdg, whereas h is height, d is density, and g is acceleration of gravity P(atm) = (hmgg)/V Therefore, in order for the spacemen to be able to breathe in their space suits and in their moon (space) modules, we have to have the atmospheric pressure available in there. This amount of air pressure has to be overcome inside of the space suits and on the visors of the helmets. The question is: Can these visors of helmets and spacesuits handle this much pressure? Earth-surface gravitational acceleration is 9.80665 m/s2 The sea level standard atmospheric pressure is 14.7 psi. One atmosphere (101 kPa or 14.7 psi) is the amount of pressure that can lift water approximately 10.3 m (34 ft). Thus, a diver 10.3 m underwater experiences a pressure of about 2 atmospheres (1 atm of air plus 1 atm of water). Therefore, a Moon Landing after Space Travel is just not possible yet.
Posted on: Mon, 19 Jan 2015 22:41:13 +0000
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