Q: Hooke’s law states that the force, F, in a spring extended by - TopicsExpress

Q: Hooke’s law states that the force, F, in a spring extended by a length x is given by F = −kx. According to Newton’s second law F = ma, where m is the mass and a is the acceleration. Calculate the dimension of the spring constant k. Answer: Given, F = -kx ⇒ k = - F/x F = ma, the dimensions of force is: [F] = ma = [M1L0T0].[M0L1T-2] = [M1L1T-2] Therefore, dimension of spring constant (k) is: [k] = [F]/[x] = [M1L1T-2].[M0L-1T0] = [M1L0T-2] or [MT-2] ..... (answer) #shahid

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