Tina is playing a game called Random Number. The game has a Wheel of Fortune containing numbers from 0 to 85 with a pointer initally at 0. The game begins when the wheel is rotated for the first time. The pointer is now at n, where n can take any value from 1 to 6. The wheel is rotated again. The pointer is now at (n + k) where k is the prime number nearest to the sum of the previous numbers where the pointer had stopped i.e. (n + 0) = n. The wheel is rotated again. The pointer is now at (n + (n + k )) + k’ where k’ is the prime number nearest to the sum of the previous numbers where the pointer had stopped i.e. (n + (n + k). (Note: If there are two equidistant prime numbers, then the larger one should be accepted.) The above pattern is followed for all subsequent rotations. If the pointer reaches 85, Tina wins the game. If it is known that Tina won the game, which of the following is a number where the pointer must have stopped? OPTIONS 1) 30 2) 18 3) 13 4) 24
Posted on: Sat, 09 Aug 2014 06:10:00 +0000
Trending Topics
Recently Viewed Topics
© 2015