Fun monday thoughts: In Newtons gravity limit, the gravitational energy of a pair of gravitation systems is given by G m1 m2/ r. This energy is negative. The energy of a self-gravitating system is essentially G m^2 / r. This energy is also negative Question: Under what circumstances the full energy of a gravitating system becomes negative? . . : . : : . : : . . . : : . Well, what is the full energy? In this case is the (positive) mass-energy (mc^2) plus the (negative) gravitational energy (G m^2 / r). It becomes negative when: mc^2 - G m^2/r < 0 mc^2 < G m^2 /r r < G m / c^2 Do you recognize that radius?
Posted on: Wed, 03 Dec 2014 07:47:34 +0000